The base is the length of the long, flat side on the bottom. The height is the distance from the base straight up to its parallel side. Which side is the base and which is height is entirely up to you – you could rotate any parallelogram to make any side the bottom and still get the same final answer. [3] X Research source
The base is the length of the long, flat side on the bottom. The height is the distance from the base straight up to its parallel side. Which side is the base and which is height is entirely up to you – you could rotate any parallelogram to make any side the bottom and still get the same final answer. [3] X Research source
For this example, assume the base has a length of 10cm.
You do not measure the height by measuring the slanted sides. [4] X Research source
For this example, assume that the height is 5cm. The height may be drawn outside of the parallelogram.
A=B∗H{\displaystyle A=BH} B=10cm;H=5cm{\displaystyle B=10cm;H=5cm} A=10cm∗5cm{\displaystyle A=10cm5cm} Area of Parallelogram=50cm2{\displaystyle =50cm^{2}}[6] X Research source
Simply square the units used to measure to get your answer. If you measured base and height in meters, your final answer would be in “meters squared,” or “m2{\displaystyle m^{2}}” If you have no measurements given, provide your answer in “units2{\displaystyle units^{2}}. “[8] X Research source
Lateral Surface Area = 2(lh+lw+hw){\displaystyle 2(lh+lw+hw)}
Remember – the height is not the length of the diagonal side – it is the distance between the side you measured for length and its parallel side. For this example, say that l=6;h=4{\displaystyle l=6;h=4}, and that you measured in inches.
Remember – the height is not the length of the diagonal side – it is the distance between the side you measured for length and its parallel side. For this example, say that l=6;h=4{\displaystyle l=6;h=4}, and that you measured in inches.
Remember – the height is not the length of the diagonal side – it is the distance between the side you measured for length and its parallel side. For this example, say that l=6;h=4{\displaystyle l=6;h=4}, and that you measured in inches.
For this example, say that the width is w=5in{\displaystyle w=5in}.
Lateral Surface Area =2(lh+lw+hw){\displaystyle =2(lh+lw+hw)} l=6in;h=4in;w=5in{\displaystyle l=6in;h=4in;w=5in} Lateral Surface Area=2(6∗4+6∗5+4∗5){\displaystyle =2(64+65+4*5)} Lateral Surface Area=2(24+30+20){\displaystyle =2(24+30+20)} Lateral Surface Area=2(74){\displaystyle =2(74)} Lateral Surface Area=148in2{\displaystyle =148in^{2}}
If you forget which units to use, simply look at the original problem. Remember that 32{\displaystyle 3^{2}} is really just a way to write out 3∗3{\displaystyle 33}. In your problem, you multiply measurements, like A=3ft∗3ft{\displaystyle A=3ft3ft}. Just like you could say that the area is 32{\displaystyle 3^{2}}, you also say the units are ft2{\displaystyle ft^{2}}. [14] X Research source
